阴圆弧推阳包络线

shouce

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阴圆弧推阳包络线

>> syms r t a b k q i A
7 w) L$ ]2 t4 b: Q; r" d4 Z>> x2=r*cos(t)+a;y2=r*sin(t)+b;
* z( `+ ^! a' p. j>> x1=-x2*cos(k*q)-y2*sin(k*q)+A*cos(q);
+ W# ^6 Q3 U5 M# p$ B" Z5 O>> y1=-x2*sin(k*q)+y2*cos(k*q)+A*sin(q);
>> simplify(diff(x1,t))

ans =
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r*sin(t - k*q)
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>> simplify(diff(y1,t))
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r*cos(t - k*q)

' E' l. H1 j* P>> simplify(diff(x1,q))
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ans =

6 T7 q+ X l4 w5 Kk*sin(k*q)*(a + r*cos(t)) - A*sin(q) - k*cos(k*q)*(b + r*sin(t))

>> simplify(diff(y1,q))
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ans =
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$ V* I% i! Q' _- p: BA*cos(q) - k*cos(k*q)*(a + r*cos(t)) - k*sin(k*q)*(b + r*sin(t))
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>> f=sym('(r*sin(t - k*q))*(A*cos(q) - k*cos(k*q)*(a + r*cos(t)) - k*sin(k*q)*(b + r*sin(t)))-r*cos(t - k*q)*(k*sin(k*q)*(a + r*cos(t)) - A*sin(q) - k*cos(k*q)*(b + r*sin(t)))')

+ [% D) N! \( H( J# q7 f>> simplify(f)

ans =

A*r*sin(q + t - k*q) + b*k*r*cos(t) - a*k*r*sin(t)
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f1=sym('A*r*sin(q + t - k*q) + b*k*r*cos(t) - a*k*r*sin(t)=0')
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>> pretty(solve(f1,q))
; m/ ~' @' g, D- J& _5 [/ / b k cos(t) - a k sin(t) \ \
| t + asin| ----------------------- | |
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| ----------------------------------- |
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(t + asin((k*(b*cos(t) - a*sin(t)))/A))/i

阳圆弧推导 阴转子包络线t + asin((k*(b*cos(t) - a*sin(t))/(A*i))
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十字背包客

这编程语言后面不加注释语句吗？别人看起来很困难呢

shouce

十字背包客 发表于 2015-12-10 09:55
0 ]( O; [/ }. c9 w+ h这编程语言后面不加注释语句吗？别人看起来很困难呢

你的意见很好 我下次改