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本帖最后由 shouce 于 2015-11-26 21:34 编辑$ s/ S* S0 q9 v3 @# X
$ H- k# T% j% a6 T4 S$ _% examlpe7.m" L6 {; T4 C$ Q% B! F: N) o1 M+ \ a=0; b=2;( }7 r5 l! R* x' ?: e eps1=1e-12;eps2=1e-12;1 F2 x; w' G. ~& H$ T, N9 t N=300; z8 P7 g) y* N+ h4 \A=[-0.104020146 35.0002164 -0.004160847];9 a% g% N8 w! \, j [m,n]=size(A);. Z, S8 [6 Q6 h3 y for i=1:m 3 m" T8 l6 \8 _: h6 }a1=A(i,1);b1=A(i,2);m1=A(i,3);, l1 F( n2 j- ]; p' T. i! I/ C end , K4 N/ h- Y* T) | Yf=@(x) ((285+60*tan(45*pi/180)-b1*sin(x)-a1*cos(x))*(a1+b1*m1)+(60)^2*x*(sin(x)-m1*cos(x))-60*285*tan(45*pi/180)*(m1*sin(x)+cos(x)));+ \/ }! W; H6 b2 a+ H Hfun=@Bisection;+ U0 e w4 b) F- A0 j [k,x,f_value]= feval(Hfun, f,a,b,eps1,eps2,N); ! l9 V8 s1 z. d8 w1 T! u" h* `2 k9 h * ^; z n% Q D0 r$ b: L" g/ j1 \ / C3 x3 ?' `, M% A 为离散点坐标及导数 中心距 285 左旋 螺旋角45度 在二分法中增加一部些程序,方便了很多: S1 m+ ?; d- W5 [" z( U0 x
1 b, W6 u; R6 W: o部分运行结果:( m' C6 s/ W0 a( [ 35, 1.303240794, 1.303240794, 1.303240794,0.000000896, 8 q; |" t& |# @0 X+ {" x36, 1.303240794, 1.303240794, 1.303240794,0.000000279,; i4 d2 g! ^) h H% @7 n6 R 37, 1.303240794, 1.303240794, 1.303240794,-0.000000030,4 C. i$ l8 j+ _+ l0 G0 e" Y3 Q 38, 1.303240794, 1.303240794, 1.303240794,0.000000124, * O" U* m7 V# o4 G9 g39, 1.303240794, 1.303240794, 1.303240794,0.000000047, 0 K" w6 V2 q7 c40, 1.303240794, 1.303240794, 1.303240794,0.000000009,+ ?1 U. u7 B" ?) g' v; f 41, 1.303240794, 1.303240794, 1.303240794,-0.000000011,4 G( f7 K+ N: r* n) `# e0 u ( p+ D; j+ }$ B * Y9 _1 U4 l/ m& C
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