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公差,这两种标注,表示意义有什么区别的?

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1#
发表于 2014-5-23 20:05:11 | 只看该作者 回帖奖励 | 倒序浏览 | 阅读模式
这两种标注,表示意义有什么区别的?

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2#
发表于 2014-5-23 20:19:55 | 只看该作者
本帖最后由 HC小丁 于 2014-5-23 20:22 编辑+ ~( q+ x( f9 ~, B6 T" L
& M( C; K q8 ~! S/ J1 j
基本尺寸不一样,实际加工尺寸可能是一样的,但设计尺寸不同
3#
发表于 2014-5-23 20:57:54 | 只看该作者
前一种标法,尺寸两侧分别加工成型,如铣或磨削两个侧面;后一种标法一般用于一个刀具完成的加工成型,如钻孔,砂轮磨槽。
4#
发表于 2014-5-23 21:00:35 | 只看该作者
对于我们加工的来说:左图我们会尽量把尺寸做到20.45至20.5之间) @+ ]4 \5 U9 O; x- v7 D+ i
右图我们会尽量把尺寸做到20.4至20.45之间
7 b5 `6 i- w/ s( m$ ^- W便于装配
5#
发表于 2014-5-23 22:20:44 | 只看该作者
是不是根据入体原则来的?
6#
发表于 2014-5-23 22:56:22 | 只看该作者
长见识了,我原先以为是个人的习惯问题,
7#
发表于 2014-5-24 10:31:03 | 只看该作者
一般是另一个部件的基本尺寸一样的
8#
发表于 2014-5-26 23:12:49 | 只看该作者
9.2.3 Converting Dimensions to Equal Bilateral Tolerances8 r! A+ J& j# A ~) N8 o
In Fig. 9-2, there were several dimensions that were toleranced using unilateral tolerances) l+ K8 q+ F* h. p2 _" b1 q6 G ?8 K
(such as .375 +.000/-.031, 3.019 +.012/-.000 and .438 +.000/-.015) or unequal bilateral tolerances (such
6 d; J! n5 q+ @# a6 y9 N# N8 kas +1.500 +.010/-.004 ). If we look at the length of the shaft, we see that there are several different ways we) r. o* N# O8 l# L+ N7 R+ |
could have applied the tolerances. Fig. 9-4 shows several ways we can dimension and tolerance the length" m2 a* p/ U( z' }" Q* f" k/ }- Z% U
of the shaft to achieve the same upper and lower tolerance limits (3.031/3.019). From a design perspective,/ ~2 w& J0 G" P, B* D* d- t
all of these methods perform the same function. They give a boundary within which the dimension is
5 W: H; m( F& i) ^4 ?' [7 l* tacceptable.; y4 g+ c& s0 @, P# z. ?1 ?( f

% Y0 \0 W2 F( H9 A& M' i1 dThe designer might think that changing the nominal dimension has an effect on the assembly. For( E0 d9 W+ Y; Y4 P
example, a designer may dimension the part length as 3.019 +.012/-.000. In doing so, the designer may8 H1 J! E+ A/ q3 h' y
falsely think that this will help minimize the gap for Requirement 1. A drawing, however, doesn’t give
i2 I( X0 k( N4 T6 N9 rpreference to any dimension within the tolerance range.
8 q/ p) p6 L* U. F" P5 MFig. 9-5 shows what happens to the manufacturing yield if the manufacturer “aims” for the dimension# ]9 h+ J2 i6 U7 C. R v
stated on the drawing and the process follows the normal distribution. In this example, if the manufacturer
t+ ?) i8 j- O* c5 N# [: naimed for 3.019, half of the parts would be outside of the tolerance zone. Since manufacturing shops want2 ]9 T5 {& }" ^) k2 M
to maximize the yield of each dimension, they will aim for the nominal that yields the largest number of
9 n/ R. @/ D* C \" V' xgood parts. This helps them minimize their costs. In this example, the manufacturer would aim for 3.025.
& q+ R5 N% O+ LThis allows them the highest probability of making good parts. If they aimed for 3.019 or 3.031, half of the* v, a) D* j+ C; ]' A
manufactured parts would be outside the tolerance limits.
3 J: S2 M- R8 Q" [As in the previous example, many manufacturing processes are normally distributed. Therefore, if we7 o7 y; Z' n- J' J) r9 s# ~& I' @
put any unilateral, or unequal bilateral tolerances on dimensions, the manufacturer would convert them to
7 ^4 S3 q+ M0 F; X9 e5 ra mean dimension with an equal bilateral tolerance. The steps for converting to an equal bilateral tolerance
' N! Y, X5 e8 |& B# Z6 jfollow.
% E, ^" B( {: P$ k- p) Y( B: {% A- E6 y0 \: u+ Q* Y
, W! B' U0 Y: [% b" R* g
1. Convert the dimension with tolerances to an upper limit and a lower limit. (For example, 3.028 +.003/% v/ M* E/ y8 l/ g
-.009 has an upper limit of 3.031 and a lower limit of 3.019.)
2 z3 l H, k( V# ~ |+ E3 R4 W5 Y2. Subtract the lower limit from the upper limit to get the total tolerance band. (3.031-3.019=.012)- y1 S$ [# L: k+ Q
3. Divide the tolerance band by two to get an equal bilateral tolerance. (.012/2=.006)
7 C i% u A0 K4. Add the equal bilateral tolerance to the lower limit to get the mean dimension. (3.019 +.006=3.025).
- @! B! O& I! F- R2 oAlternately, you could subtract the equal bilateral tolerance from the upper limit. (3.031-.006=3.025)0 E; h' B7 ?9 ^# D* Y& g* l

8 j7 |5 M0 L9 {8 SAs a rule, designers should use equal bilateral tolerances. Sometimes, using equal bilateral tolerances, d' ^( Y0 t/ B4 X1 I' w" ^
may force manufacturing to use nonstandard tools. In these cases, we should not use equal bilateral& d' V9 ]" c0 a; W4 ?- Z0 L7 Y
tolerances. For example, we would not want to convert a drilled hole diameter from Æ.125 +.005/-.001 to6 G4 X1 N2 U2 X% x) ~
Æ.127 ±.003. In this case, we want the manufacturer to use a standard Æ.125 drill. If the manufacturer sees
+ n; }6 F3 w KÆ.127 on a drawing, he may think he needs to build a special tool. In the case of drilled holes, we would+ {) O' E3 {0 J
also want to use an unequal bilateral tolerance because the mean of the drilling process is usually larger
; R- F( f. [. e' Cthan the standard drill size. These dimensions should have a larger plus tolerance than minus tolerance.
3 d* R- L4 n- ]% ]7 i2 QAs we will see later, when we convert dimensions to equal bilateral tolerances, we don’t need to keep9 X/ [( U' g; j
track of which tolerances are “positive” and which tolerances are “negative” because the positive toler-0 e: u/ u! W6 d1 M- _
ances are equal to the negative tolerances. This makes the analysis easier. Table 9-1 converts the neces-7 z: M6 r/ _& Q% y" p0 Z
sary dimensions and tolerances to mean dimensions with equal bilateral tolerances.6 U& y' h& T. f
8 K1 b' c, D, r& `

7 n9 Q( _- ^" {* }# u; Z7 u"Dimensioning and Tolerancing Handbook, by Paul J. Drake, Jr."3 k( u( D, N: ]' p

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9#
发表于 2014-5-27 08:32:12 | 只看该作者
我来看看高手们怎么说,我对这些太不熟悉了,这几天看书貌似看懂了,其实还是不懂
10#
发表于 2014-5-27 16:02:09 | 只看该作者
左图,尺寸尽量避开20.4
+ U- y3 D6 i% u7 p0 `右图,尽量把尺寸避开20.5

点评

恩,我也有这么个想法,但不知怎么讲的,看你你说的顿时感觉就是这个意思 发表于 2014-5-29 20:45
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