2266998 发表于 2011-10-25 12:22 " O& B0 X( T+ M2 y- X3 [0 ]0 x% d
齿轮与滚刀位置定了,理论上的啮合点就定了,啮进、啮出就是确定的了,既然你有了共轭线,就应当有了交点, ... % C$ P, a; U+ d' T+ c! z# J
方程这样的
- P2 |& C2 m7 D0 q8 N( H xat = ((r - r * Sin(αn) - ha) * Tan(αn) - sn1) / Cos(β)% a1 }% D5 @5 n) W N
xbt = (-sn1 / 2 + (h - ha) * Tan(αn)) / Cos(β)9 {- C. `! b1 ]6 J! A
yat = r - r * Sin(αn) - ha
: I5 x; j: n& [; Y4 \, m' M x1 = λa
; `& ?; N7 T6 H! w/ z: U y1 = yat + (λa - xat) * Atan(αn) * Cos(β)
$ S3 q* Q0 \5 e; U( W" s ψ = (x1 + y1 * Atan(αn) * Cos(β)) / r1/ `' U F* y1 a6 I
x2 = Cos(ψ) * x1 + Sin(ψ) * y1 + r1 * (Sin(ψ) - ψ * Cos(ψ))
" C: o- K$ B0 A( ^; k+ C" t y2 = -Sin(ψ) * x1 + Cos(ψ) * y1 + r1 * (Cos(ψ) + ψ * Sin(ψ)); O- ~" r; M& }5 e
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xet = xat - r * Cos(αn) / Cos(β)* |* E$ Q2 n% y! x
x3 = xet + r * Sin(λe) / Cos(β)* k; |; a4 I. e1 w, t8 T
y3 = -ha + r - r * Cos(λe)( W8 F8 j, m+ k) o
ψ1 = (x3 + y3 * Atan(αn) * Cos(β)) / r1 q$ x8 |. H+ b; e( @
x4 = Cos(ψ1) * x3 + Sin(ψ1) * y3 + r1 * (Sin(ψ1) - ψ1 * Cos(ψ1))- `8 t7 p/ C3 H8 D" ?4 x; b0 e7 d+ p
y4 = -Sin(ψ1) * x3 + Cos(ψ1) * y3 + r1 * (Cos(ψ1) + ψ1 * Sin(ψ1))
: r% C7 p2 n) J- ]" t0 Mλa,λe是在一定的范围内,联立方程组怎么解啊
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