案例之老外做的手工计算与软件分析相结合

寂静天花板

人家没把基础丢了，全文转载。

For this post I decided to test out something that I learned in my mechanical vibrations class which is calculating the natural frequency of a semi-ring. This ring can be seen above with some of the basic dimensions. Below are my hand calculations to find the frequency. The subscript G is referring to the center of gravity whereas the subscript O is referring to the geometric center of the ring. Gravity is the restoring force that is acting on the ring when the center of gravity is past the geometric center of ring. I found the maximum kinetic and potential energy of the ring due to the fact that the total energy in the system is the kinetic plus the potential. When the ring is at is farthest position, the potential energy will be at the max and there will be no kinetic energy. When the ring is passing through its equilibrium the kinetic energy will be at its maximum and there will be no potential energy. Due to the fact that the total energy in the system is not changing they can be set equal to each other. Solving this for the natural frequency will result in a relatively simple formula that is seen at the bottom of my hand calculations.
* ~* Q5 L, K5 Y7 h
7 _4 W/ ]7 x, z  a/ t6 OThe next step was to create the model in SolidWorks and create a motion study. I used motion analysis to create a study using gravity and had an initial displacement of the ring. In the first study I just used a tangent mate to keep the contact but I also created another study in which I used solid body contact with friction. This acted as a damper and reduced the amplitude over time. Once I ran the study I plotted the y component of linear displacement selecting the upper edge of the ring and the base plate as a reference. This gave me the graph that you see below.
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4 Z' {9 E5 H# rTo find the frequency of oscillation I right clicked in the graph and selected export CSV. This gave me data points that I was able to open in Excel. With this open I determined the number of cycles per second. This turned out to be approximately 1.1 Hz which is relatively close to the 1.04 Hz that was calculated using the equations. Feel free to check out the model below and try to calculate the natural frequency of a different sized ring but make sure to have motion analysis added in
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SAESUNLAND

工作严谨呀，这就是为什么能设计出好的设备的细节之一

倚剑踏破乱红尘

还是要好好学

zhuxuwei8

说实话，我看到英语就头疼，直接是硬着头皮看完的。。。

忧郁包子

国外家庭作业而已

设计者AF

设计者AF 发表于 2012-12-30 12:50
5 v) ~7 F% e: F3 ^* G; D准备寒假搞基础，力学 数学！回老家潜心学

难是肯定的，，趁现在有浓厚的兴趣，享受机械！{:soso_e182:}
8 W1 j3 ]! Z' y1 K. x

设计者AF

设计者AF 发表于 2012-12-30 12:50
: F7 a6 s. R4 _8 ^( n( n. g准备寒假搞基础，力学 数学！回老家潜心学

也是啊，，就看能学多少了，，趁现在有浓厚的兴趣，享受机械的乐趣就好！{:soso_e182:}

张志彬1989

佩服，学习

斗志

看到全是英文头就开始大了  

Dreaming___snai

第一眼感觉像机械原理那本书………………苦     逼

qdtruck

世界就怕认真二字！