非圆齿轮二次开发

lijun1226

画齿廓，为什么最高点不在齿顶高那里。感觉不对。大家能看看我的程序吗？Dim i As Integer
* g0 m5 H# W$ sReDim x0(18)
ReDim y0(18)
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. Z; U- t( l' f9 G; D9 d) r' t& h& wDim k0 As Integer
ReDim p0(18)
$ r$ q- _& m. ], y" rReDim q0(18)
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! A' {+ s9 t9 C' D) WDim h0 As Integer
ReDim p00(18)
1 h' v& o& E" R9 p6 C4 eReDim q00(18)


u = Sqr((Da / Db) ^ 2 - 1)
g = u / 14
3 y2 r/ \! V& {/ g. S) v4 {

xx = 0.5 * Da * Sin(Tan(f) - f)
) Q& C" k0 l4 _+ z6 h; \) r, g, Oyy = 0.5 * Da * Cos(Tan(f) - f)

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5 B$ q+ t: l7 N; h
6 W5 d+ A- ~+ o7 j% F3 k( I9 s) ~s = pi * m / 2
( m0 C  p2 |6 u- ~' H5 f8 Jinva = Tan(a) - a
sb = Cos(a) * (s + m * z * inva)
- G5 M  T: b( |. E- O# o9 ^j = 2 * sb / Db
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t = 0

For i = 1 To 14
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If t <= u Then

/ Y5 S. v' Z& I3 X7 s$ v+ \' {x0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
- D! A; o  M- T& E' t! m5 J( Hy0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)
, ]7 I1 I/ o, z0 n  Q# T1 b7 j+ Y
p00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
) g4 ]9 n5 X1 @+ @; x+ ]) fq00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)

& ~; I1 }, Z9 W& f9 {t = t + g

3 n6 H2 P- y" l- X9 np0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
End If
: n) O4 ^7 w, C$ L5 KNext i
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Part.SetPickMode
xx = 0
yy = 0.5 * Df
Xx1 = xx * Cos(j) + yy * Sin(j)
Yy1 = xx * Sin(j) + yy * Cos(j)
+ m2 }6 m  p. M* W2 H, Q
, W+ A5 U6 V& O0 A* M! qp000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
q000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0)


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Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0
Part.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
Part.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
1 u2 Z; Y$ M3 N8 l% D& LPart.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0
( ~; m" T# Z7 ^2 w8 tPart.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0
) |0 z0 @( Q% E* XPart.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
Part.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
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Part.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
, X4 g; I2 f: L$ pPart.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
Part.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0
" M. f0 a/ I6 `" A( J5 `Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
7 S+ Q, Y5 r5 ~Part.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0
! F) s. [( \& u* `3 F: uPart.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
Part.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0
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Part.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
Part.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
Part.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
Part.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 0
5 A: t7 {+ u- e- y- d4 S$ H: t  Q9 HPart.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0
Part.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
Part.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0
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# B! E6 E0 y  u0 P5 gPart.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 0
Part.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
Part.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0
& K; X. D1 `# }+ b6 yPart.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 0
& W% m; K* w) @$ |0 L+ Q: l4 F, MPart.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0
Part.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 0
# ]& c8 a# a. v" ?. j% {Part.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 0

George_W4TBo

是solidworks的二开吗，真费劲哥都比较摈弃，这是最近做的一个单边连续，单边步进机构的其中一对非圆齿轮，在家里所以图不多，有空再更新，欢迎交流